Remember double replacement?
Now we have double replacement with solubility.
Now we have to put the states of matter signs beside in compound in a balanced equation
E.g. (g), (l), (aq), (s)
Lets take a double replacement reaction.
2 K3PO3 + 3Cu(NO3)2 -------> 1Cu3(PO3)2 + 6 KNO3
http://nobel.scas.bcit.ca/chem0010/unit8/solubilityRules.htm Here are the solubility rules:
Look at the products. Use the solubility sheet to see whether Cu will react with PO3. Do the same for K and NO3
Since Cu and PO3 do not react, they are a solid (s).
K and NO3 do react and will be (aq)
It will look like this:
2K3PO3 + 3 Cu(NO3)2 ------> 1 Cu3(PO3)2 (s) + 6 KNO3(aq)
The equation will look like this
2K3PO3 (aq) + Cu(NO3)2(aq) -----> 1 Cu3(PO3)2 (s) + 6 KNO3(aq)
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