Lab 2E was done in class on November the second. It involved find the thickness of aluminum foil by ways of mathematical formulas.
Equipment:
3 Rectangular pieces of aluminum foil
Centigram balance
Ruler
Procedure:
Obtain 3 pieces of aluminum foil. The foil was then measured twice for both width and length on each end to determine to average length of the side. This was done to minimize experimental error.A centigram balance was then used to find the mass of each piece of aluminum foil.
Results:
The thickness of the aluminum foil was determined by two algebraic equations.
D (density) = m/V (mass/volume)
V = LWH ( length x Width x Height)
The mass, length and width were all known from previous measurements taken in the lab. The mathematical procedure was as follows:
D = m/V
2.7 = 1.04/(16.8)(14.55)(h)
2.7 = 1.04/244.44(h)
(244.44h)(2.7)= 244.44h(1.04/244.44h)
The 244.44h's then cancel on the right side.
687.204h/687.204= 1.04/687.204
h = .001513378
h = 1.51 x 10^-3cm
This same operation was performed for all three pieces of aluminum foil because each had a different length and width then the other two.
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